Friday, April 28, 2006
APDC2
12 days to go...
Rightfully, most of you are getting your hw in and are showing an effort (which is beyond crucial at this final stage of the class). You will not be reminded or warned if you do not hand in your hw ON TIME. As I have repeatedly warned, you may see an F for the 4th quarter if you continue to not hand in your hw. Doing the hw and not handing it in is masochistic. Good day.
Major errors on the part I exam:
Q75: I knew that this question was coming so I did it TWICE IN CLASS LAST WEEK! Most of you did not think/draw/show work/read your direct example in the notes otherwise you would have known the correct answer.
To purify an ore of a precious metal (like Cu), in an electrolytic cell, make the impure ore the ANODE and put a pure bar of the precious metal at the cathode; then electrolyze the sample and the precious metal will oxidize into its cations which will then be reduced onto the pure metal at the cathode. The contaminating metal will either react with the water of the solution or will not be as easily reduced at the cathode (by choosing an appropriate applied voltage to the cell) so it usually ends up as "mud" at the bottom of the cell. DON'T FORGET THIS AGAIN.
Rightfully, most of you are getting your hw in and are showing an effort (which is beyond crucial at this final stage of the class). You will not be reminded or warned if you do not hand in your hw ON TIME. As I have repeatedly warned, you may see an F for the 4th quarter if you continue to not hand in your hw. Doing the hw and not handing it in is masochistic. Good day.
Major errors on the part I exam:
Q75: I knew that this question was coming so I did it TWICE IN CLASS LAST WEEK! Most of you did not think/draw/show work/read your direct example in the notes otherwise you would have known the correct answer.
To purify an ore of a precious metal (like Cu), in an electrolytic cell, make the impure ore the ANODE and put a pure bar of the precious metal at the cathode; then electrolyze the sample and the precious metal will oxidize into its cations which will then be reduced onto the pure metal at the cathode. The contaminating metal will either react with the water of the solution or will not be as easily reduced at the cathode (by choosing an appropriate applied voltage to the cell) so it usually ends up as "mud" at the bottom of the cell. DON'T FORGET THIS AGAIN.
# posted by C @ 12:56 PM 
